linux - Formatting text in BASH -

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i absolute beginner shell scripting. task make script, show functions used in file (caller , callee). have used objdump, grep, awk etc. output:

000000000040090d <usage>: 000000000040095d <failure>:   400970:   e8 98 ff ff ff          callq  40090d <usage> 000000000040097f <strton>:   4009bc:   e8 9c ff ff ff          callq  40095d <failure> 00000000004009c6 <main>:   400a0e:   e8 6c ff ff ff          callq  40097f <strton>   400a26:   e8 32 ff ff ff          callq  40095d <failure>   400a41:   e8 39 ff ff ff          callq  40097f <strton>   400a59:   e8 ff fe ff ff          callq  40095d <failure>   400a9a:   e8 fe ff ff          callq  40095d <failure>   400aae:   e8 cc fe ff ff          callq  40097f <strton>   400ac2:   e8 b8 fe ff ff          callq  40097f <strton>   400ad1:   e8 87 fe ff ff          callq  40095d <failure>   400afe:   e8 fe 01 00 00          callq  400d01 <set_timeout>   400b1c:   e8 3c fe ff ff          callq  40095d <failure>   400b26:   e8 19 00 00 00          callq  400b44 <print_fib_upto>   400b37:   e8 89 00 00 00          callq  400bc5 <print_ackermann>

okay, result should this:

failure -> usage strton -> failure main -> failure main -> print_ackermann main -> print_fib_upto main -> set_timeout main -> strton

but have no idea how accomplish it. i'd know how in c, etc, not here. think right pseudo-code.

if (end of line == ">:")          caller == last column;          while (end of line == ">") {                    callee == last column;                    echo "$caller -> $callee"          }

can tell me, how write in bash? thank much, maybe it's silly question, don't know anyting shell yet.

you can use awk:

awk -f'[<>:]+' 'nf==3{p=$(nf-1); next} {print p, "->", $(nf-1)}' file failure -> usage strton -> failure main -> strton main -> failure main -> strton main -> failure main -> failure main -> strton main -> strton main -> failure main -> set_timeout main -> failure main -> print_fib_upto main -> print_ackermann

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