arrays - PHP: array_diff count issue due to multiple similar name -

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how can match similar words in array_diff count

problem of multiple name single words tv-television,inches-inch,mobile-mobile phones,mobile-phones.so create wrong percentage in array_diff count

example :

    $str1 = "samsung television 21 inches led bh005de";     $str2 = "samsung 21 inch led tv";      $arr1 = explode(' ', $str1);     $arr2 = explode(' ', $str2);      $differencecount = count(array_diff($arr2, $arr1));

in above str1 , str2 contain television,tv , inches,inch words..how can solve problem

the obvious way use synonyms that:

$str1 = "samsung television 21 inches led bh005de"; $str2 = "samsung 21 inch led tv";  //synonyms: $syns = [    'tv'   => ['tv', 'television'],    'inch' => ['inch', 'inches'] ];  //replace: $str1 = array_reduce(array_keys($syns), function($c, $x) use ($syns) {    return $c = preg_replace('/\b'.join('\b|\b', $syns[$x]).'\b/', $x, $c); }, $str1); //now, str1 looks "samsung tv 21 inch led bh005de"  $str2 = array_reduce(array_keys($syns), function($c, $x) use ($syns) {    return $c = preg_replace('/\b'.join('\b|\b', $syns[$x]).'\b/', $x, $c); }, $str2); //now, str2 looks "samsung 21 inch led tv"  $arr1 = explode(' ', $str1); $arr2 = explode(' ', $str2);   //var_dump(array_diff($arr1, $arr2));//['bh005de']

in case can't rely on sort of word forms (like inch - inches) - because need parse abbreviations - , cases specific meanings. thus, using synonyms may way resolve matter cases.


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