python - Counting items in list before consecutive instance -

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i'd count amount of items in array before consecutive amount of zeroes inputted user. 

['1', '0', '1', '0', '0', '0', '0', '0', '0', '0', 'e']

for example, if user inputs 3, there 3 items in list before consecutive amount of 3 zeroes.

at moment code checks amount of consecutive zeroes , returns based on - how can change gain value of items before consecutive instance?

largeblock = max(sum(1 _ in g) k, g in groupby(line) if k == '0') 

seats, wanted = ['1', '0', '1', '0', '0', '0', '0', '0', '0', '0', 'e'], 3 itertools import groupby occ, grp in groupby(enumerate(seats[:-1], 1), key = lambda x: x[1]):     if occ == '0':         available = list(grp)         if len(available) >= wanted:             print([seats[-1] + str(item[0]) item in available[:wanted]])  # ['e4', 'e5', 'e6']

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