c pointer with function and money -

write program dispense change. user enters amount paid , amount due. program determines how many dollars, quarters, dimes, nickels, , pennies should given change. ask user 2 inputs (amount due , amount paid) in main() , send these along pointers 5 parameters (dollars, quarters, dimes, nickels, pennies) function called change(), calculate number of each give out. print results main().

what wrong program now. compiles no problems answer wrong wrong.

#include <stdio.h> #include <conio.h>  //function prototype void change( int *d, int *q, int *di, int *n, int *p, int paid, int due );  int main() {     //variables     int paid;     int due;     int dollars;     int quarters;     int dimes;     int nickels;     int pennies;      //reference variables     int *d;     int *q;     int *di;     int *n;     int *p;      printf( "enter amount due: \n" );     scanf( "%d", &due );      printf( "enter amount paid: \n" );     scanf( "%d", &paid );      change( &dollars, &quarters, &dimes, &nickels, &pennies, paid, due );      printf( "dollars = %d\nquarters = %d\ndimes =%d\nnickels = %d\npennies = %d", dollars, quarters, dimes, nickels, pennies );      getch();     return 0; }  void change( int *d, int *q, int *di, int *n, int *p, int paid, int due ) {     int dm;     int qm;     int dim;     int nm;     int pm;     int modu;     int modu2;     int modu3;     int total;     int penniestotal;      total = due - paid;      penniestotal = total * 100;      dm = penniestotal / 100;     modu = penniestotal % 100;     qm = modu / 25;     modu2 = modu % 25;     dim = modu2 / 10;     modu3 = modu2 % 10;     nm = modu3 / 5;     pm = modu3 % 5; } 

you declare/define function as

void change(int *d,int *q,int *di, int *n, int *p, int paid, int due ) 

and call as

change(paid,due,&dollars,&quarters,&dimes,&nickels,&pennies); 

the first 2 params paid , due passed integers while function expects integer pointers.

seems want pass them last , second last parameters.