Python to search a string for the first occurrence of any item in a list -

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i have parse few thousand txt documents using python, right i'm getting code working one.

i trying find first time month (january, february, march, etc) appears in document, , return position of first month. every document has @ least 1 month in it, have many months.

this works currently, seems cumbersome:

mytext = open('2.txt','r') mytext = mytext.read()  january = mytext.find("january") february = mytext.find("february") march = mytext.find("march") april = mytext.find("april") may = mytext.find("may") june = mytext.find("june") july = mytext.find("july") august = mytext.find("august") september = mytext.find("september") october = mytext.find("october") november = mytext.find("november") december = mytext.find("december")  monthpos = [january, february, march, april, may, june, july, august, september, october, november, december] monthpos = [x x in monthpos if x != -1] print min(monthpos)  # returns first match number

i combine any() , find() job done, there doesn't seem better way this. found this question isn't clear, didn't much. while know wrong , not work many reasons, here want do:

mytext = open('text.txt','r') mytext = mytext.read() months = ["january", "february", "march", "april", "may", "june", "july", "august", "september", "october", "november", "december"] print mytext.find(months) #where find first time month matched 1945 # return location in string first month found

thanks in advance.

i think want:

months = ["january", "february", "march", "april",            "may", "june", "july", "august",            "september", "october", "november", "december"] indices = [s.find(month) month in months] first = min(index index in indices if index > -1)

first, first appearance of each month (or -1 if not present), minimum of indices, except it's -1. throw valueerror if none found, may or may not want.

as two-bit alchemist has commented, short-cut efficiency:

months = ["january", "february", "march", "april",            "may", "june", "july", "august",            "september", "october", "november", "december"] first = none month in sorted(months, key=len):     = s[:first].find(month) # search first part of string     if != -1:         if < first or first none:             first =         if < len(month): # not enough room remaining months             break

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