linux - Check if a directory exists and is accessible -

i want check if directory exists , has access rights; if does, perform tasks. code wrote, might not have proper syntax.

can me correct it?

dir_test=/data/abc/xyz if (test -d $dir_test & test –x $dir_test -eq 0);  cd $dir_test fi

i believe can written this.

dir_test=/data/abc/xyz test -d $dir_test if [ $? -eq 0 ]; test –x $dir_test if [ $? -eq 0 ]; cd $dir_test fi fi

how can write more efficiently?

the best way write original test-based solution be

if test -d "$dir_test" && test –x "$dir_test";     cd $dir_test fi

although if test fails , don't change directories? remainder of script not work expected.

you can shorten using [ synonym test:

if [ -d "$dir_test" ] && [ -x "$dir_test" ];

or can use conditional command provided bash:

if [[ -d "$dir_test" && -x "$dir_test" ]];

the best solution, since going change directories if tests succeed, try it, , abort if fails:

cd "$dir_test" || {   # take appropriate action; 1 option exit   # error.   exit 1 }

Sp